Fix app name duplicating error

appsubscriptiontask
Ashvini Wegodapola 7 months ago
parent 464214fe1b
commit d3ac0ce5b0

@ -2423,21 +2423,22 @@ public class ApplicationManagerImpl implements ApplicationManager {
int tenantId = PrivilegedCarbonContext.getThreadLocalCarbonContext().getTenantId(true);
String userName = PrivilegedCarbonContext.getThreadLocalCarbonContext().getUsername();
ApplicationDTO applicationDTO = getApplication(applicationId);
String sanitizedName = ApplicationManagementUtil.sanitizeName(applicationUpdateWrapper.getName(),
Constants.ApplicationProperties.NAME );
try {
ConnectionManagerUtil.beginDBTransaction();
if (!StringUtils.isEmpty(applicationUpdateWrapper.getName()) && !applicationDTO.getName()
.equals(applicationUpdateWrapper.getName())) {
if (!StringUtils.isEmpty(sanitizedName) && !applicationDTO.getName()
.equals(sanitizedName)) {
if (applicationDAO
.isExistingAppName(applicationUpdateWrapper.getName().trim(), applicationDTO.getDeviceTypeId(),
.isExistingAppName(sanitizedName.trim(), applicationDTO.getDeviceTypeId(),
tenantId)) {
String msg = "Already an application registered with same name " + applicationUpdateWrapper.getName()
String msg = "Already an application registered with same name " + sanitizedName
+ ". Hence you can't update the application name from " + applicationDTO.getName() + " to "
+ applicationUpdateWrapper.getName();
+ sanitizedName;
log.error(msg);
throw new BadRequestException(msg);
}
applicationDTO.setName(ApplicationManagementUtil.sanitizeName(applicationUpdateWrapper.getName(),
Constants.ApplicationProperties.NAME));
applicationDTO.setName(sanitizedName);
}
if (!StringUtils.isEmpty(applicationUpdateWrapper.getSubMethod()) && !applicationDTO.getSubType()
.equals(applicationUpdateWrapper.getSubMethod())) {

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